Frazier Chang
06/26/2023 · High School
e) \( \sqrt[3]{-64} \) es un \( n^{\circ} \) irracional
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Step-by-step Solution
La expresión \( \sqrt[3]{-64} \) se refiere a la raíz cúbica de \(-64\). Para calcularlo, podemos observar que:
\[
\sqrt[3]{-64} = -4
\]
Esto se debe a que \((-4) \times (-4) \times (-4) = -64\).
El número \(-4\) es un número entero y, por lo tanto, es un número racional, ya que puede expresarse como el cociente de dos enteros (por ejemplo, \(-4 = \frac{-4}{1}\)).
Por lo tanto, la afirmación de que \( \sqrt[3]{-64} \) es un \( n^{\circ} \) irracional es incorrecta. En realidad, \( \sqrt[3]{-64} \) es un número racional.
Quick Answer
\( \sqrt[3]{-64} = -4 \), es un número racional.
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