Solve the system of equations: \( 1 / 2 x-y=10, y=3 / 2 x-8 \) what is the value of ( 6 , 3 ?

Solve the system of equations \( \frac{1}{2}x-y=10;y=\frac{3}{2}x-8 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}\frac{1}{2}x-y=10\\y=\frac{3}{2}x-8\end{array}\right.\) - step1: Substitute the value of \(y:\) \(\frac{1}{2}x-\left(\frac{3}{2}x-8\right)=10\) - step2: Simplify: \(-x+8=10\) - step3: Move the constant to the right side: \(-x=10-8\) - step4: Subtract the numbers: \(-x=2\) - step5: Change the signs: \(x=-2\) - step6: Substitute the value of \(x:\) \(y=\frac{3}{2}\left(-2\right)-8\) - step7: Simplify: \(y=-11\) - step8: Calculate: \(\left\{ \begin{array}{l}x=-2\\y=-11\end{array}\right.\) - step9: Check the solution: \(\left\{ \begin{array}{l}x=-2\\y=-11\end{array}\right.\) - step10: Rewrite: \(\left(x,y\right) = \left(-2,-11\right)\) The solution to the system of equations is \( x = -2 \) and \( y = -11 \). Therefore, the value of \( (6, 3) \) is not a solution to the system of equations.