Mccarthy Vaughn
04/24/2024 · Primary School
QUESTION 5 Given \( f(x)=\sin x-1 \) and \( g(x)=2 \cos x \) for \( 0^{\circ} \leq x \leq 270^{\circ} \). S.1 Sketch, on the grid provided in the ANSWER BOOK, the graph of \( f \) and for \( 0^{\circ} \leq x \leq 270^{\circ} \). Write down the following: 5.2.1 Amplitude of \( g \) 5.2.2 Range of \( f \) Use your graph to determine the following: 5.3.1 Number of solutions to \( f(x)=g(x) \) in the interval \( 0^{\circ} \leq x \leq 270^{\circ} \) \( 5.3 .2 \quad \) Value(s) of \( x \) in the interval \( 0^{\circ} \leq x \leq 180^{\circ} \) for which \( \sin x=2+2 \cos x \)
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Amplitude of \( g \) = 2.
Range of \( f \) = \([-2, 0]\).
Number of solutions to \( f(x) = g(x) \) = 3.
Value of \( x \) = 180°.
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