Hodgson Hanson
05/16/2023 · High School
The point \( \left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right) \) is on the terminal side of an angle. Find the six trig functions for the given angle. \( \sin \theta= \) \( \cos \theta= \) \( \tan \theta= \) What is the measure of the angle \( \theta \) in radians? \( \sec \theta= \) (Round to four decimal places) What is the measure of the angle in degrees?
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Step-by-step Solution
To find the six trigonometric functions for the angle whose terminal side passes through the point \(\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)\), we start by identifying the coordinates of the point as \( (x, y) \) where \( x = \frac{\sqrt{2}}{2} \) and \( y = \frac{\sqrt{2}}{2} \).
### Step 1: Calculate the radius \( r \)
The radius \( r \) is calculated using the formula:
\[
r = \sqrt{x^2 + y^2}
\]
Substituting the values of \( x \) and \( y \):
\[
r = \sqrt{\left(\frac{\sqrt{2}}{2}\right)^2 + \left(\frac{\sqrt{2}}{2}\right)^2} = \sqrt{\frac{2}{4} + \frac{2}{4}} = \sqrt{\frac{2}{2}} = \sqrt{1} = 1
\]
### Step 2: Calculate the trigonometric functions
Now we can find the six trigonometric functions:
1. **Sine**:
\[
\sin \theta = \frac{y}{r} = \frac{\frac{\sqrt{2}}{2}}{1} = \frac{\sqrt{2}}{2}
\]
2. **Cosine**:
\[
\cos \theta = \frac{x}{r} = \frac{\frac{\sqrt{2}}{2}}{1} = \frac{\sqrt{2}}{2}
\]
3. **Tangent**:
\[
\tan \theta = \frac{y}{x} = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1
\]
4. **Cosecant** (the reciprocal of sine):
\[
\csc \theta = \frac{1}{\sin \theta} = \frac{1}{\frac{\sqrt{2}}{2}} = \frac{2}{\sqrt{2}} = \sqrt{2}
\]
5. **Secant** (the reciprocal of cosine):
\[
\sec \theta = \frac{1}{\cos \theta} = \frac{1}{\frac{\sqrt{2}}{2}} = \frac{2}{\sqrt{2}} = \sqrt{2}
\]
6. **Cotangent** (the reciprocal of tangent):
\[
\cot \theta = \frac{1}{\tan \theta} = \frac{1}{1} = 1
\]
### Summary of the trigonometric functions
- \( \sin \theta = \frac{\sqrt{2}}{2} \)
- \( \cos \theta = \frac{\sqrt{2}}{2} \)
- \( \tan \theta = 1 \)
- \( \csc \theta = \sqrt{2} \)
- \( \sec \theta = \sqrt{2} \)
- \( \cot \theta = 1 \)
### Step 3: Find the angle \( \theta \)
The coordinates \(\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)\) correspond to an angle of \( \frac{\pi}{4} \) radians (or 45 degrees) in the first quadrant.
### Step 4: Convert to degrees
To convert radians to degrees:
\[
\theta = \frac{\pi}{4} \times \frac{180}{\pi} = 45^\circ
\]
### Final Answers
- \( \sin \theta = \frac{\sqrt{2}}{2} \)
- \( \cos \theta = \frac{\sqrt{2}}{2} \)
- \( \tan \theta = 1 \)
- \( \sec \theta = \sqrt{2} \) (approximately \( 1.4142 \) when rounded to four decimal places)
- Measure of the angle \( \theta \) in radians: \( \frac{\pi}{4} \)
- Measure of the angle in degrees: \( 45^\circ \)
Quick Answer
- \( \sin \theta = \frac{\sqrt{2}}{2} \)
- \( \cos \theta = \frac{\sqrt{2}}{2} \)
- \( \tan \theta = 1 \)
- \( \sec \theta = \sqrt{2} \)
- Measure of the angle \( \theta \) in radians: \( \frac{\pi}{4} \)
- Measure of the angle in degrees: \( 45^\circ \)
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