The solubility in water of ionic compound \( X \) is measured and found to be \( 63.3 \frac{\mathrm{~g}}{\mathrm{~L}} \) at \( 30 .{ }^{\circ} \mathrm{C} \). Calculate the volume of a saturated solution of \( X \) in water that would contain 23.0 g of \( X \) at this temperature. Be sure your answer has the correct unit symbol and 3 significant digits.

To find the volume of a saturated solution of ionic compound \( X \) that contains 23.0 g of \( X \), we can use the solubility information provided. The solubility of \( X \) is given as \( 63.3 \, \text{g/L} \). This means that in 1 liter of saturated solution, there are 63.3 grams of \( X \). To find the volume of the solution that contains 23.0 g of \( X \), we can set up a proportion based on the solubility: \[ \text{Volume} = \frac{\text{mass of } X}{\text{solubility}} = \frac{23.0 \, \text{g}}{63.3 \, \text{g/L}} \] Now, we can calculate the volume: \[ \text{Volume} = \frac{23.0 \, \text{g}}{63.3 \, \text{g/L}} \approx 0.363 \, \text{L} \] To express this in the correct unit and with three significant digits, we convert liters to milliliters: \[ 0.363 \, \text{L} = 363 \, \text{mL} \] Thus, the volume of the saturated solution of \( X \) that would contain 23.0 g of \( X \) at \( 30 \, ^\circ \text{C} \) is: \[ \boxed{363 \, \text{mL}} \]