Wright Cruz
05/02/2024 · Senior High School
Determine whether the equation is linear or not. Then graph the equation by finding and plotting ordered-pair solutions. \( y=x^{2}-6 \)
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Step-by-step Solution
To determine whether the equation \( y = x^2 - 6 \) is linear or not, we need to analyze its form. A linear equation can be expressed in the standard form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
In the given equation, \( y = x^2 - 6 \), the term \( x^2 \) indicates that this is a quadratic equation, not a linear one. Therefore, the equation is **not linear**.
### Graphing the Equation
To graph the equation, we can find some ordered-pair solutions by substituting different values for \( x \) and calculating the corresponding \( y \) values.
Let's choose a few values for \( x \):
1. **When \( x = -3 \)**:
\[
y = (-3)^2 - 6 = 9 - 6 = 3 \quad \Rightarrow \quad (-3, 3)
\]
2. **When \( x = -2 \)**:
\[
y = (-2)^2 - 6 = 4 - 6 = -2 \quad \Rightarrow \quad (-2, -2)
\]
3. **When \( x = -1 \)**:
\[
y = (-1)^2 - 6 = 1 - 6 = -5 \quad \Rightarrow \quad (-1, -5)
\]
4. **When \( x = 0 \)**:
\[
y = 0^2 - 6 = 0 - 6 = -6 \quad \Rightarrow \quad (0, -6)
\]
5. **When \( x = 1 \)**:
\[
y = 1^2 - 6 = 1 - 6 = -5 \quad \Rightarrow \quad (1, -5)
\]
6. **When \( x = 2 \)**:
\[
y = 2^2 - 6 = 4 - 6 = -2 \quad \Rightarrow \quad (2, -2)
\]
7. **When \( x = 3 \)**:
\[
y = 3^2 - 6 = 9 - 6 = 3 \quad \Rightarrow \quad (3, 3)
\]
### Ordered-Pair Solutions
The ordered pairs we found are:
- \( (-3, 3) \)
- \( (-2, -2) \)
- \( (-1, -5) \)
- \( (0, -6) \)
- \( (1, -5) \)
- \( (2, -2) \)
- \( (3, 3) \)
### Plotting the Points
You can plot these points on a coordinate plane. The graph of the equation \( y = x^2 - 6 \) will be a parabola that opens upwards, with its vertex at the point \( (0, -6) \).
### Summary
- The equation \( y = x^2 - 6 \) is **not linear**; it is a quadratic equation.
- The graph is a parabola, and the ordered pairs provide points to plot on the graph.
Quick Answer
The equation \( y = x^2 - 6 \) is quadratic, not linear. The graph is a parabola with vertex at \( (0, -6) \). Points on the graph include \( (-3, 3) \), \( (-2, -2) \), \( (-1, -5) \), \( (0, -6) \), \( (1, -5) \), \( (2, -2) \), and \( (3, 3) \).
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