Drag each number to show whether or not it is a solution to the inequality shown. Inequality: \( 20 \geq 5+3 x \)

To determine whether each number is a solution to the inequality \(20 \geq 5 + 3x\), we need to substitute each number into the inequality and check if the inequality holds true. Given inequality: \(20 \geq 5 + 3x\) Let's substitute each number into the inequality and check: 1. For \(x = 1\): Substitute \(x = 1\) into the inequality: \(20 \geq 5 + 3(1)\) \(20 \geq 5 + 3\) \(20 \geq 8\) This is true, so \(x = 1\) is a solution to the inequality. 2. For \(x = 2\): Substitute \(x = 2\) into the inequality: \(20 \geq 5 + 3(2)\) \(20 \geq 5 + 6\) \(20 \geq 11\) This is true, so \(x = 2\) is a solution to the inequality. 3. For \(x = 3\): Substitute \(x = 3\) into the inequality: \(20 \geq 5 + 3(3)\) \(20 \geq 5 + 9\) \(20 \geq 14\) This is true, so \(x = 3\) is a solution to the inequality. 4. For \(x = 4\): Substitute \(x = 4\) into the inequality: \(20 \geq 5 + 3(4)\) \(20 \geq 5 + 12\) \(20 \geq 17\) This is true, so \(x = 4\) is a solution to the inequality. Therefore, all the numbers \(x = 1, 2, 3, 4\) are solutions to the inequality \(20 \geq 5 + 3x\).