Janine has been trying a capital murder case for the better part of a month. During this time, she has repeatedly spoken with the press and revealed much about her opinion on the case and various aspects of it. For what is Janine at risk of getting in trouble? Trying her case "in the press" Attempting to produce a diversion Offering qualified immunity to the defendant Refusing her right to absolute immunity

4. Halla la ecuación de una recta paralela a la recta dada y que pase por el punto que se indica. \( \begin{array}{ll}\text { a. } y=7 x-4 & M(1,2) \\ \text { b. } 3 x+6 y-2=0 & N(3,0) \\ \text { c. } y=-\frac{3}{4} x-16 & P\left(\frac{1}{3}, \frac{2}{5}\right) \\ \text { d. } 4 x+y-2=0 & Q\left(-\frac{1}{3},-\frac{7}{2}\right)\end{array} \)

[6.4] En los ejercicios 61-70 resuelve cada ecuación. \( \begin{array}{llll}\text { 61. } \frac{3}{4}=\frac{12}{x} & \text { 62. } \frac{x}{1.5}=\frac{x-4}{4.5} & \text { 63. } \frac{3 x+4}{5}=\frac{2 x-8}{3} & \text { 64. } \frac{x}{4.8}+\frac{x}{2}=1.7 \\ \text { 65. } \frac{2}{y}+\frac{1}{5}=\frac{3}{y} & \text { 66. } \frac{2}{x+4}-\frac{3}{x-4}=\frac{-11}{x^{2}-16} & \text { 67. } \frac{x}{x^{2}-9}+\frac{2}{x+3}=\frac{4}{x-3} \\ \text { 68. } \frac{7}{x^{2}-5}+\frac{3}{x+5}=\frac{4}{x-5} & \text { 69. } \frac{x-3}{x-2}+\frac{x+1}{x+3}=\frac{2 x^{2}+x+1}{x^{2}+x-6} & \text { 70. } \frac{x+1}{x+3}+\frac{x+2}{x-4}=\frac{2 x^{2}-18}{x^{2}-x-12}\end{array} \)

5. Für \( k>0 \) ist die Funktion \( f_{k} \) gegeben durch \( f_{k}(x)=x^{3}-k^{2} x \). Berechnen Sie \( k \) so, dass der Graph von \( f_{k} \) mit der \( x \)-Achse eine Fläche mit dem Inhalt 8 einschließt.

Abner is a prosecutor acting as an advocate for the government in a case in which he is trying hard to secure a conviction. While arguing the case, Abner used false testimony and also failed to disclose exculpatory evidence at trial. Which of the following statements is true? Abner cannot be held liable for either action Abner can be held liable for using false testimony at trial Abner can be held liable for failing to disclose exculpatory evidence at Abner can be held liable for both of these actions

Perimetro axpresen en la unidad indicada a. \( 0,05 \mathrm{~km}= \) b. \( 2,5 \mathrm{dm}= \) c. \( 1235 \mathrm{~cm}= \) d. \( 3500 \mathrm{~mm}= \) e. \( 7,5 \mathrm{hm}= \) f. \( 0,034 \mathrm{~km}= \)