If $$ 2 x-5 y=10 $$ and $$ y=6 $$, which of the following shows how to apply substitution method correctly? $$ \begin{array}{l}2 x+5(6)=10 \ 02(6)+5 y=10 \ 02(6)+5(6)=10 \ 2 x+5 y=10(6)\end{array} $$

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$$ 2x - 5(6) = 10 $$ To apply the substitution method correctly, we need to substitute the value of $$ y $$ into the first equation and solve for $$ x $$. Given: 1. $$ 2x - 5y = 10 $$ 2. $$ y = 6 $$ Substitute the value of $$ y $$ into the first equation: $$ 2x - 5(6) = 10 $$ Simplify the equation: $$ 2x - 30 = 10 $$ Add 30 to both sides: $$ 2x = 40 $$ Divide by 2 to solve for $$ x $$: $$ x = 20 $$ Therefore, the correct substitution method is: $$ 2x - 5(6) = 10 $$

If \( 2 x-5 y=10 \) and \( y=6 \), which of the following shows how to apply substitution method correctly? \( \begin{array}{l}2 x+5(6)=10 \\ 02(6)+5 y=10 \\ 02(6)+5(6)=10 \\ 2 x+5 y=10(6)\end{array} \)

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If \( 2 x-5 y=10 \) and \( y=6 \), which of the following shows how to apply substitution method correctly? \( \begin{array}{l}2 x+5(6)=10 \\ 02(6)+5 y=10 \\ 02(6)+5(6)=10 \\ 2 x+5 y=10(6)\end{array} \)

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