$$ KMnO _ { 2 } + HCl \rightarrow \lambda KCl + MnCle _ { 2 } + H _ { 6 } O + Cl _ { 2 } $$

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The balanced reaction of $$ KMnO_4 $$ with $$ HCl $$ produces $$ KCl $$, $$ MnCl_2 $$, $$ H_2O $$, and $$ Cl_2 $$. The balanced equation is $$ 2 KMnO_4 + 16 HCl \rightarrow 2 KCl + 2 MnCl_2 + 8 H_2O + 5 Cl_2 $$. The reaction you've written involves potassium permanganate ($$ KMnO_4 $$) reacting with hydrochloric acid ($$ HCl $$). However, there are some inaccuracies in the products and the overall stoichiometry. The balanced reaction for potassium permanganate with hydrochloric acid typically produces potassium chloride ($$ KCl $$), manganese(II) chloride ($$ MnCl_2 $$), water ($$ H_2O $$), and chlorine gas ($$ Cl_2 $$). The balanced equation for this reaction is: $$ 2 KMnO_4 + 16 HCl \rightarrow 2 KCl + 2 MnCl_2 + 8 H_2O + 5 Cl_2 $$ In this equation: - $$ KMnO_4 $$ is the potassium permanganate. - $$ HCl $$ is hydrochloric acid. - $$ KCl $$ is potassium chloride. - $$ MnCl_2 $$ is manganese(II) chloride. - $$ H_2O $$ is water. - $$ Cl_2 $$ is chlorine gas. Make sure to adjust the coefficients to balance the equation properly if you are working with a different stoichiometry or specific conditions.

\( KMnO _ { 2 } + HCl \rightarrow \lambda KCl + MnCle _ { 2 } + H _ { 6 } O + Cl _ { 2 } \)

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\( KMnO _ { 2 } + HCl \rightarrow \lambda KCl + MnCle _ { 2 } + H _ { 6 } O + Cl _ { 2 } \)

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