Hill Wagner
08/04/2024 · Elementary School
The number of foreign students enrolled in a certain college is approximated by the equation \( S=10 t+500 \), where \( t \) is the number of years since 1990 and \( S \) is the number of foreign students. Granh the equation for \( t=0.2 .6 .14 \).
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Tutor-Verified Answer
Step-by-step Solution
To graph the equation \( S = 10t + 500 \) for different values of \( t \), you will need to calculate the corresponding \( S \) values for each \( t \) and then plot the points on a graph. Here's how you can do it for the given values of \( t \):
1. For \( t = 0.2 \):
\( S = 10(0.2) + 500 \)
\( S = 2 + 500 \)
\( S = 502 \)
So, the point is (0.2, 502).
2. For \( t = 0.6 \):
\( S = 10(0.6) + 500 \)
\( S = 6 + 500 \)
\( S = 506 \)
So, the point is (0.6, 506).
3. For \( t = 1.4 \):
\( S = 10(1.4) + 500 \)
\( S = 14 + 500 \)
\( S = 514 \)
So, the point is (1.4, 514).
Now, to graph these points:
- Start by plotting the point (0.2, 502) on the graph.
- Plot the point (0.6, 506) on the same graph.
- Plot the point (1.4, 514) on the same graph.
Since the equation is linear, you can draw a straight line through these points to represent the graph of the equation \( S = 10t + 500 \). The line will extend in both directions, showing how the number of foreign students \( S \) changes as the number of years \( t \) since 1990 increases.
Quick Answer
For \( t = 0.2 \), \( S = 502 \); for \( t = 0.6 \), \( S = 506 \); for \( t = 1.4 \), \( S = 514 \). Plot these points and draw a straight line through them to graph the equation \( S = 10t + 500 \).
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