Encuentra un valor de \( x \) que sea solución de la ecuación: \( \left(x^{2}-2\right)^{2}-10\left(x^{2}-2\right)+21=0 \) \( x=\square \)

Solve the equation \( (x^{2}-2)^{2}-10(x^{2}-2)+21=0 \). Solve the equation by following steps: - step0: Solve for \(x\): \(\left(x^{2}-2\right)^{2}-10\left(x^{2}-2\right)+21=0\) - step1: Calculate: \(x^{4}-14x^{2}+45=0\) - step2: Factor the expression: \(\left(x-3\right)\left(x+3\right)\left(x^{2}-5\right)=0\) - step3: Separate into possible cases: \(\begin{align}&x-3=0\\&x+3=0\\&x^{2}-5=0\end{align}\) - step4: Solve the equation: \(\begin{align}&x=3\\&x=-3\\&x=\sqrt{5}\\&x=-\sqrt{5}\end{align}\) - step5: Rewrite: \(x_{1}=-3,x_{2}=-\sqrt{5},x_{3}=\sqrt{5},x_{4}=3\) La ecuación dada es \( (x^{2}-2)^{2}-10(x^{2}-2)+21=0 \). Las soluciones para \( x \) son \( x=-3 \), \( x=-\sqrt{5} \), \( x=\sqrt{5} \) y \( x=3 \).