3. Solve the Janet waters her garden three times a week. Last week she used \( 39 \frac{1}{2} \ell, 56 \mathrm{l} \) and 300 ml and 38000 ml . How much water did Janet use altogether? b) Nomhle has \( 12 \frac{1}{2} \mathrm{l} \) of milk and she sells \( 8 \frac{1}{4} \ell \). How much does Nomhle have left over? c) Solly has seven containers and he pours three 250 ml bottles of juice into each. How much juice does Solly need for this? d) Josh has 4 litres of fruit juice to share equally between six friends. How much can each friend have?

\( \left. \begin{array} { l }{ f ^ { \prime } ( x ) = \lim _ { h \rightarrow 0 } \frac { ( x + h ) ^ { 4 } - x ^ { 4 } } { h } \quad \quad | ( a + b ) ^ { 4 } = a ^ { 4 } + 4 a ^ { 3 } b + 6 a ^ { 2 } b ^ { 2 } + 4 a b ^ { 3 } + b ^ { 4 } } \\ { = \lim _ { h \rightarrow 0 } \frac { x ^ { 4 } + 4 x ^ { 3 } h + 6 x ^ { 2 } h ^ { 2 } + 4 x h ^ { 3 } + h ^ { 4 } - x ^ { 3 } } { h } } \\ { = \lim _ { h \rightarrow 0 } ( 4 x ^ { 3 } + 6 x ^ { 2 } h + 4 x h ^ { 2 } + h ^ { 3 } ) } \\ { = \square } \end{array} \right. \)

UNDATOINPII Un sub e immerso in mare ed é soggetto a una pressione è di \( 2,0 \mathrm{~atm} \). Il corpo del sub occupa un volume di 72 L . La densità dell'acqua di mare è \( 1030 \mathrm{~kg} / \mathrm{m}^{3} \). Determina a quale profondità si trova il sub.

A Block \( A(\mathrm{~m}=3.0 \mathrm{~kg}) \) with a speed of \( 3.0 \mathrm{~m} / \mathrm{s} \) collides with a block \( B(\mathrm{~m}=10.0 \mathrm{~kg}) \), moving again with a speed of \( 2.0 \mathrm{~m} / \mathrm{s} \). After the collision, block B travels in the same direction as before the collision with a speed of \( 0.5 \mathrm{~m} / \mathrm{s} \). The magnitude of the velocity of block A after the collision is: \( -2 \mathrm{~m} / \mathrm{s} \) \( 2 \mathrm{~m} / \mathrm{s} \) \( 7 \mathrm{~m} / \mathrm{s} \) \( -7 \mathrm{~m} / \mathrm{s} \) \( 10 \mathrm{~m} / \mathrm{s} \) \( -10 \mathrm{~m} / \mathrm{s} \)

What is the value of \( x^{0} \).assuming \( x \neq 0 ? \)

Die zweite Ableitung der ganzrationalen Funktion \( g(x)=-x^{5}+2 x^{4}+x \) ist \[ g^{\prime \prime}(x)=-20 x^{3}+24 x^{2} \] Bestimme die vierte Ableitung \( g^{(4)}(x) \) A \( g^{(4)}(x)=1 \)