Willis Turnbull
02/25/2024 · High School
Вариант 4 1.) \( \frac{9}{5} \cdot \frac{2}{3}= \) 2.) \( \frac{15}{4}: \frac{3}{7}= \) 3.) \( \frac{1}{5}-\frac{3}{4}= \) 4.) \( \frac{1}{10}+\frac{21}{50}= \) 5.) \( \left(\frac{17}{26}+\frac{11}{13}\right) \cdot \frac{17}{6}= \)
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Tutor-Verified Answer
Step-by-step Solution
Давайте решим каждое из заданий по порядку.
1.) \( \frac{9}{5} \cdot \frac{2}{3} = \frac{9 \cdot 2}{5 \cdot 3} = \frac{18}{15} = \frac{6}{5} \) (после сокращения на 3).
2.) \( \frac{15}{4} : \frac{3}{7} = \frac{15}{4} \cdot \frac{7}{3} = \frac{15 \cdot 7}{4 \cdot 3} = \frac{105}{12} = \frac{35}{4} \) (после сокращения на 3).
3.) \( \frac{1}{5} - \frac{3}{4} = \frac{4}{20} - \frac{15}{20} = \frac{4 - 15}{20} = \frac{-11}{20} \).
4.) \( \frac{1}{10} + \frac{21}{50} = \frac{5}{50} + \frac{21}{50} = \frac{5 + 21}{50} = \frac{26}{50} = \frac{13}{25} \) (после сокращения на 2).
5.) \( \left(\frac{17}{26} + \frac{11}{13}\right) \cdot \frac{17}{6} \).
Сначала найдем сумму в скобках:
\( \frac{11}{13} = \frac{22}{26} \), поэтому:
\( \frac{17}{26} + \frac{22}{26} = \frac{39}{26} = \frac{3}{2} \) (после сокращения на 13).
Теперь умножим:
\( \frac{3}{2} \cdot \frac{17}{6} = \frac{3 \cdot 17}{2 \cdot 6} = \frac{51}{12} \).
Таким образом, ответы на задания:
1.) \( \frac{6}{5} \)
2.) \( \frac{35}{4} \)
3.) \( \frac{-11}{20} \)
4.) \( \frac{13}{25} \)
5.) \( \frac{51}{12} \)
Quick Answer
1.) \( \frac{6}{5} \)
2.) \( \frac{35}{4} \)
3.) \( \frac{-11}{20} \)
4.) \( \frac{13}{25} \)
5.) \( \frac{51}{12} \)
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