A certain molecular compound \( M \) has a solubility in hexane of \( 0.663 \frac{\mathrm{~g}}{\mathrm{~mL}} \) at \( 20 .{ }^{\circ} \mathrm{C} \). Calculate the greatest mass of \( M \) that could be dissolved in 7.0 L of hexane at this temperature. You may assume the volume of the solution doesn't change as the \( M \) is dissolved. Be sure your answer has the correct unit symbol and 2 significant digits.

To calculate the greatest mass of \( M \) that could be dissolved in 7.0 L of hexane at \( 20.0^{\circ} \mathrm{C} \), we can use the given solubility of \( M \) in hexane. Given: - Solubility of \( M \) in hexane: \( 0.663 \frac{\mathrm{~g}}{\mathrm{~mL}} \) - Volume of hexane: 7.0 L First, we need to convert the volume of hexane from liters to milliliters since the solubility is given in grams per milliliter. 1 L = 1000 mL So, 7.0 L = 7.0 * 1000 mL = 7000 mL Now, we can calculate the mass of \( M \) that could be dissolved in 7000 mL of hexane using the solubility of \( M \) in hexane. Mass of \( M \) = Solubility of \( M \) in hexane * Volume of hexane Mass of \( M \) = \( 0.663 \frac{\mathrm{~g}}{\mathrm{~mL}} \) * 7000 mL Let's calculate the mass of \( M \) in grams. Calculate the value by following steps: - step0: Calculate: \(0.663\times 7000\) - step1: Multiply the numbers: \(4641\) The greatest mass of \( M \) that could be dissolved in 7.0 L of hexane at \( 20.0^{\circ} \mathrm{C} \) is 4641 grams.