Choose the concect answer which function has a domain $$ D=]-\infty ; 2[u] 2 ;+\infty[ $$ ? $$ \begin{array}{ll} ext { 1) } f(x)=\frac{x+1}{x-2} & ext { 2) } f(x)=1+x^{2} \ ext { 3) } f(x)=\frac{1}{\sqrt{x-2}}\end{array} $$

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Choose the concect answer which function has a domain $$ D=]-\infty ; 2[u] 2 ;+\infty[ $$ ? $$ \begin{array}{ll}	ext { 1) } f(x)=\frac{x+1}{x-2} & 	ext { 2) } f(x)=1+x^{2} \ 	ext { 3) } f(x)=\frac{1}{\sqrt{x-2}}\end{array} $$

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The function with the domain $$ D = ]-\infty ; 2[ \cup ]2 ; +\infty[ $$ is $$ f(x) = \frac{x+1}{x-2} $$.

Choose the concect answer which function has a domain \( D=]-\infty ; 2[u] 2 ;+\infty[ \) ? \( \begin{array}{ll}\text { 1) } f(x)=\frac{x+1}{x-2} & \text { 2) } f(x)=1+x^{2} \\ \text { 3) } f(x)=\frac{1}{\sqrt{x-2}}\end{array} \)

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Choose the concect answer which function has a domain \( D=]-\infty ; 2[u] 2 ;+\infty[ \) ? \( \begin{array}{ll}\text { 1) } f(x)=\frac{x+1}{x-2} & \text { 2) } f(x)=1+x^{2} \\ \text { 3) } f(x)=\frac{1}{\sqrt{x-2}}\end{array} \)

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