Floyd Delgado
10/30/2023 · Junior High School
5. As coordenadas do ponto de mínimo da função de segundo grau \( f(x)=x^{2}-4 x+5 \) são (A) \( (-1,-2) \) (B) \( (1,-2) \) (C) \( (-2,-1) \) (D) \( (2,1) \) (E) \( (2,2) \)
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Step-by-step Solution
Para encontrar as coordenadas do ponto de mínimo da função de segundo grau \( f(x) = x^2 - 4x + 5 \), podemos usar a fórmula do vértice da parábola, que é dada por:
\[
x_v = -\frac{b}{2a}
\]
onde \( a \) e \( b \) são os coeficientes da função \( f(x) = ax^2 + bx + c \).
No nosso caso, temos:
- \( a = 1 \)
- \( b = -4 \)
Substituindo os valores na fórmula do vértice:
\[
x_v = -\frac{-4}{2 \cdot 1} = \frac{4}{2} = 2
\]
Agora, precisamos encontrar o valor de \( f(x_v) \) para determinar a coordenada \( y \) do ponto de mínimo:
\[
f(2) = (2)^2 - 4(2) + 5
\]
\[
f(2) = 4 - 8 + 5
\]
\[
f(2) = 1
\]
Portanto, as coordenadas do ponto de mínimo são \( (2, 1) \).
A resposta correta é (D) \( (2, 1) \).
Quick Answer
As coordenadas do ponto de mínimo são \( (2, 1) \).
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