Mann Fernandez
05/24/2024 · Elementary School
Tentukan nilai dari \( \left(\frac{f}{g}\right)(x) \) jika diketahui fungsi \( f(x)= \) \( x^{2}+x-6 \) dan \( g(x)=x+3 \)
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Untuk menentukan nilai dari \( \left(\frac{f}{g}\right)(x) \), kita perlu menghitung \( \frac{f(x)}{g(x)} \).
Diberikan:
\[
f(x) = x^2 + x - 6
\]
\[
g(x) = x + 3
\]
Maka, kita dapat menuliskan:
\[
\left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)} = \frac{x^2 + x - 6}{x + 3}
\]
Selanjutnya, kita akan menyederhanakan pecahan tersebut. Pertama, kita faktorkan \( f(x) \):
\[
f(x) = x^2 + x - 6 = (x - 2)(x + 3)
\]
Sekarang kita substitusikan faktorisasi ini ke dalam pecahan:
\[
\frac{f(x)}{g(x)} = \frac{(x - 2)(x + 3)}{x + 3}
\]
Selama \( x + 3 \neq 0 \) (yaitu \( x \neq -3 \)), kita dapat menyederhanakan pecahan tersebut:
\[
\frac{(x - 2)(x + 3)}{x + 3} = x - 2
\]
Jadi, nilai dari \( \left(\frac{f}{g}\right)(x) \) adalah:
\[
\left(\frac{f}{g}\right)(x) = x - 2 \quad \text{untuk } x \neq -3
\]
Quick Answer
\( \left(\frac{f}{g}\right)(x) = x - 2 \) untuk \( x \neq -3 \)
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