Which fraction results in a terminating decimal? $$ \frac{1}{12} $$ $$ \frac{4}{9} $$ $$ \frac{2}{15} $$ $$ \frac{7}{8} $$

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$$ \frac{7}{8} $$ A fraction results in a terminating decimal if, when it is in its simplest form, the denominator has only the prime factors 2 and/or 5. Let's analyze each of the given fractions: 1. **$$ \frac{1}{12} $$**: - The prime factorization of 12 is $$ 2^2 \times 3 $$. - Since 3 is a prime factor other than 2 or 5, $$ \frac{1}{12} $$ does not result in a terminating decimal. 2. **$$ \frac{4}{9} $$**: - The prime factorization of 9 is $$ 3^2 $$. - Since 3 is a prime factor other than 2 or 5, $$ \frac{4}{9} $$ does not result in a terminating decimal. 3. **$$ \frac{2}{15} $$**: - The prime factorization of 15 is $$ 3 \times 5 $$. - Since 3 is a prime factor other than 2 or 5, $$ \frac{2}{15} $$ does not result in a terminating decimal. 4. **$$ \frac{7}{8} $$**: - The prime factorization of 8 is $$ 2^3 $$. - Since the only prime factor is 2, $$ \frac{7}{8} $$ results in a terminating decimal. Thus, the fraction that results in a terminating decimal is: $$ \frac{7}{8} $$

Which fraction results in a terminating decimal? \( \frac{1}{12} \) \( \frac{4}{9} \) \( \frac{2}{15} \) \( \frac{7}{8} \)

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Which fraction results in a terminating decimal? \( \frac{1}{12} \) \( \frac{4}{9} \) \( \frac{2}{15} \) \( \frac{7}{8} \)

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