Mills Parsons
08/12/2024 · Senior High School
\( i \int _ { j } \sqrt { \frac { z ^ { 4 } + z ^ { 2 } + 1 } { z ^ { 2 } } } ( \frac { z ^ { 2 } - 1 } { z ^ { 2 } + 1 } ) d z \)
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Per risolvere l'integrale \(i \int _ { j } \sqrt { \frac { z ^ { 4 } + z ^ { 2 } + 1 } { z ^ { 2 } } } \left( \frac { z ^ { 2 } - 1 } { z ^ { 2 } + 1 } \right) d z\), semplifichiamo l'espressione sotto la radice e consideriamo un cambio di variabile o una sostituzione per procedere con l'integrazione.
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