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02/21/2023 · Junior High School
If \( f(x)=2 \sin x+11 \cos x \), then \( f^{\prime}(x)=2 \cos (x)-11 \sin (x) \) \( f^{\prime}(5)= \)
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Step-by-step Solution
要解这个问题,我们需要求出函数 \( f(x) = 2 \sin x + 11 \cos x \) 的导数 \( f'(x) \),然后计算 \( f'(5) \) 的值。
### 步骤 1:求导数 \( f'(x) \)
首先,我们知道 \( f(x) = 2 \sin x + 11 \cos x \)。
根据导数的线性性质,我们可以分别对 \( 2 \sin x \) 和 \( 11 \cos x \) 求导,然后将结果相加。
- \( \frac{d}{dx} (2 \sin x) = 2 \cos x \)
- \( \frac{d}{dx} (11 \cos x) = 11 (-\sin x) = -11 \sin x \)
因此,\( f'(x) \) 为:
\[ f'(x) = 2 \cos x - 11 \sin x \]
### 步骤 2:计算 \( f'(5) \)
现在我们已经得到了 \( f'(x) = 2 \cos x - 11 \sin x \),接下来我们需要计算 \( f'(5) \)。
将 \( x = 5 \) 代入 \( f'(x) \) 中:
\[ f'(5) = 2 \cos 5 - 11 \sin 5 \]
### 最终答案
因此,\( f'(5) = 2 \cos 5 - 11 \sin 5 \)。
Quick Answer
\( f'(5) = 2 \cos 5 - 11 \sin 5 \)
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