A store manager needs to order two different products, Product \( X \) eosts \( \$ 12 \) per unit, and Product \( Y \) costs \( \$ 9 \) per unit. The manager has \( \$ 115 \) to spend on a combination of these products. If the manager decides to buy 5 units of Product \( X \), what is the maximum whole number of units of Product \( Y \) that the manager can buy?

Let's denote the number of units of Product \( Y \) that the manager can buy as \( y \). Given: - The cost of Product \( X \) is \( \$12 \) per unit. - The cost of Product \( Y \) is \( \$9 \) per unit. - The manager has \( \$115 \) to spend on a combination of these products. - The manager decides to buy 5 units of Product \( X \). We can set up the following equation to represent the total cost of the products: \[ 12 \times 5 + 9y = 115 \] Now, we can solve this equation to find the maximum whole number of units of Product \( Y \) that the manager can buy. Solve the equation by following steps: - step0: Solve for \(y\): \(12\times 5+9y=115\) - step1: Multiply the numbers: \(60+9y=115\) - step2: Move the constant to the right side: \(9y=115-60\) - step3: Subtract the numbers: \(9y=55\) - step4: Divide both sides: \(\frac{9y}{9}=\frac{55}{9}\) - step5: Divide the numbers: \(y=\frac{55}{9}\) The manager can buy a maximum of 6 units of Product \( Y \) if they decide to buy 5 units of Product \( X \).