Savage Stewart
04/09/2024 · Elementary School
\( \operatorname { ta } \alpha = \frac { ( \frac { 3 } { 1 } - \frac { 1 } { 10 } ) } { 1 + i \frac { 1 } { 10 } ) ( \frac { 3 } { 7 } ) } \)
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Para resolver la expresión \( \operatorname{ta} \alpha = \frac{ \left( \frac{3}{1} - \frac{1}{10} \right) }{ \left( 1 + i \frac{1}{10} \right) \left( \frac{3}{7} \right) } \), primero simplificamos el numerador y el denominador por separado. El numerador es 2.9 y el denominador se simplifica para obtener \( \frac{909}{4900} \). Finalmente, multiplicamos 2.9 por el recíproco del denominador y multiplicamos el resultado por el numerador simplificado.
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