2. Resuelva el siguiente sistema ntilizando el método de igualación: \[ \left\{\begin{array}{l}3 x+y=7 \\ 2 x-y=3\end{array}\right. \]

Solve the system of equations \( 3x+y=7; 2x-y=3 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}3x+y=7\\2x-y=3\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}y=7-3x\\2x-y=3\end{array}\right.\) - step2: Substitute the value of \(y:\) \(2x-\left(7-3x\right)=3\) - step3: Simplify: \(5x-7=3\) - step4: Move the constant to the right side: \(5x=3+7\) - step5: Add the numbers: \(5x=10\) - step6: Divide both sides: \(\frac{5x}{5}=\frac{10}{5}\) - step7: Divide the numbers: \(x=2\) - step8: Substitute the value of \(x:\) \(y=7-3\times 2\) - step9: Simplify: \(y=1\) - step10: Calculate: \(\left\{ \begin{array}{l}x=2\\y=1\end{array}\right.\) - step11: Check the solution: \(\left\{ \begin{array}{l}x=2\\y=1\end{array}\right.\) - step12: Rewrite: \(\left(x,y\right) = \left(2,1\right)\) El sistema de ecuaciones se resuelve utilizando el método de eliminación y se obtiene la solución: \( (x,y) = (2,1) \).