Dada la siguiente función definida a trozos, determinar los valores de a y \( \mathbf{b} \) que hacen que sea continua. \[ f(x)=\left\{\begin{array}{cl}a-x^{2} & \text { si, } \quad x \leq 0 \\ 2 & \text { si, } 0

1. \( 3 \times 0.45= \)

What is the purpose of a \( 90 \% \) confidence interval? to estimate the value of \( \mu \) with an interval of reasonable values to give a range of values for the data to tell us the level of confidence

b. \( 2 \frac{4}{5} \div 1 \frac{1}{15} \)

(iii) \( \left\{\begin{aligned} x_{1}-5 x_{2}-x_{3}+12 x_{4}-x_{5} & =-4 \\ -2 x_{1}+10 x_{2}+3 x_{3}-33 x_{4}+2 x_{5}+x_{6} & =4 \\ x_{3}-9 x_{4}+x_{5} & =8 \\ x_{1}-5 x_{2}+2 x_{3}-15 x_{4}+2 x_{5}+x_{6} & =14\end{aligned}\right. \)

Solve: \( 5 x+8=-11 x+3 \)