May Horton
05/29/2023 · High School

Q11 Solve and compare. -2-(-2) \( (-2)+(-2) \). Q12 Find the sum by suitable rearrangement. \( 18+12+1982+488 \). Q13 Q14 Find the least number which when divided by 45,15 and 18 leaves remainder 5 in each case.

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### Q11: Solve and compare. -2 - (-2) = 0, (-2) + (-2) = -4. 0 is greater than -4. ### Q12: Find the sum by suitable rearrangement. 18 + 12 + 1982 + 488 = 2500. ### Q14: Find the least number which when divided by 45, 15, and 18 leaves remainder 5 in each case. The least number is 95.

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