Hodges Johnston
11/10/2023 · Senior High School
(b) A swimming pool is being filled. At the deepest point, the depth of the water in the pool at any instant is \( h \mathrm{~m} \). The volume of water in the pool \( V \mathrm{~m}^{3} \) is given by \[ V(h)=20 h^{2}+40 h \] Find the rate at which the volume of water is changing with respect to the depth when th water in the pool is 0.75 m deep.
UpStudy ThothAI Solution
Tutor-Verified Answer
Quick Answer
The rate of change of volume with respect to depth at 0.75 m is 70 \( \text{m}^3/\text{m} \).
Step-by-step Solution
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit