Park Long
08/16/2023 · Primary School
\( \left. \begin{array} { c c } { - A = \left( \begin{array} { c c c } { 3 } & { 1 } & { 3 } \\ { - 1 } & { 0 } & { - 1 } \\ { 2 } & { 5 } & { 3 } \end{array} \right) } & { B = \left( \begin{array} { c c c } { 7 } & { 3 } & { - 1 } \\ { 2 } & { 8 } & { 7 } \\ { - 1 } & { - 2 } & { - 3 } \end{array} \right) } \\ { A \times B } & { A + B } \\ { B \times A } & { B - A } \end{array} \right. \)
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Step-by-step Solution
To solve the problem, we need to perform matrix operations involving the matrices \( A \) and \( B \). First, we need to find the matrix \( A \) from the given information that \( -A \) is provided.
Given:
\[
-A = \begin{pmatrix} 3 & 1 & 3 \\ -1 & 0 & -1 \\ 2 & 5 & 3 \end{pmatrix}
\]
Thus, we can find \( A \) by multiplying by -1:
\[
A = -\begin{pmatrix} 3 & 1 & 3 \\ -1 & 0 & -1 \\ 2 & 5 & 3 \end{pmatrix} = \begin{pmatrix} -3 & -1 & -3 \\ 1 & 0 & 1 \\ -2 & -5 & -3 \end{pmatrix}
\]
Now we have:
\[
A = \begin{pmatrix} -3 & -1 & -3 \\ 1 & 0 & 1 \\ -2 & -5 & -3 \end{pmatrix}
\]
\[
B = \begin{pmatrix} 7 & 3 & -1 \\ 2 & 8 & 7 \\ -1 & -2 & -3 \end{pmatrix}
\]
### 1. Calculate \( A \times B \)
To multiply \( A \) and \( B \):
\[
A \times B = \begin{pmatrix} -3 & -1 & -3 \\ 1 & 0 & 1 \\ -2 & -5 & -3 \end{pmatrix} \times \begin{pmatrix} 7 & 3 & -1 \\ 2 & 8 & 7 \\ -1 & -2 & -3 \end{pmatrix}
\]
Calculating each element of the resulting matrix:
- First row:
- \( (-3)(7) + (-1)(2) + (-3)(-1) = -21 - 2 + 3 = -20 \)
- \( (-3)(3) + (-1)(8) + (-3)(-2) = -9 - 8 + 6 = -11 \)
- \( (-3)(-1) + (-1)(7) + (-3)(-3) = 3 - 7 + 9 = 5 \)
- Second row:
- \( (1)(7) + (0)(2) + (1)(-1) = 7 + 0 - 1 = 6 \)
- \( (1)(3) + (0)(8) + (1)(-2) = 3 + 0 - 2 = 1 \)
- \( (1)(-1) + (0)(7) + (1)(-3) = -1 + 0 - 3 = -4 \)
- Third row:
- \( (-2)(7) + (-5)(2) + (-3)(-1) = -14 - 10 + 3 = -21 \)
- \( (-2)(3) + (-5)(8) + (-3)(-2) = -6 - 40 + 6 = -40 \)
- \( (-2)(-1) + (-5)(7) + (-3)(-3) = 2 - 35 + 9 = -24 \)
Thus, we have:
\[
A \times B = \begin{pmatrix} -20 & -11 & 5 \\ 6 & 1 & -4 \\ -21 & -40 & -24 \end{pmatrix}
\]
### 2. Calculate \( A + B \)
Now, we add \( A \) and \( B \):
\[
A + B = \begin{pmatrix} -3 & -1 & -3 \\ 1 & 0 & 1 \\ -2 & -5 & -3 \end{pmatrix} + \begin{pmatrix} 7 & 3 & -1 \\ 2 & 8 & 7 \\ -1 & -2 & -3 \end{pmatrix}
\]
Calculating each element:
- First row: \( -3 + 7 = 4 \), \( -1 + 3 = 2 \), \( -3 - 1 = -4 \)
- Second row: \( 1 + 2 = 3 \), \( 0 + 8 = 8 \), \( 1 + 7 = 8 \)
- Third row: \( -2 - 1 = -3 \), \( -5 - 2 = -7 \
Quick Answer
\( A \times B = \begin{pmatrix} -20 & -11 & 5 \\ 6 & 1 & -4 \\ -21 & -40 & -24 \end{pmatrix} \)
\( A + B = \begin{pmatrix} 4 & 2 & -4 \\ 3 & 8 & 8 \\ -3 & -7 & -3 \end{pmatrix} \)
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