The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.9 cm . a. Find the probability that an individual distance is greater than 213.40 cm . b. Find the probability that the mean for 15 randomly selected distances is greater than 198.50 cm . c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30 ? a. The probability is (Round to four decimal places as needed.)

те их в порядке возрастания: \( 4 \sqrt{2} ; 2 \sqrt{7} ; 3 \sqrt{5} \) ия:

Find the derivative. \[ y=8 t^{2}+\frac{16}{\sqrt{t}}-\frac{7}{t^{2}} \]

For the following quadratic equation, determine the nature of the roots. \[ x^{2}-8 x+41=0 \]

Evaluate the expression. \( v=10 \quad w=3 \) \( 2 v+4 w \)

\( \left. \begin{array} { c } { \int \frac { d y } { y \ln ^ { 2 } y } = \int \frac { d y } { y ( \ln y ) ^ { 2 } } } \\ { = \int \frac { 1 } { ( \ln y ) ^ { 2 } } \frac { d y } { y } } \\ { w = \ln y } \\ { d w = \frac { 1 } { y } d y } \\ { d w = \frac { d y } { y } } \\ { = \int \frac { 1 } { w ^ { 2 } } d w } \\ { = \int w ^ { - 2 } d w } \end{array} \right. \)