Coles Huang
11/07/2023 · Middle School
a) \( \begin{array}{rl}\text { Resuelve por lgualacion: } \\ 5 \mathrm{y} 2 & 2 \\ \mathrm{x} y 2 & =2 \\ +\end{array} \) b) Resuelve por reducción: \( \left\{\begin{aligned} 5 \mathrm{x} y 3 & = \\ -2 \mathrm{x}+4 \mathrm{y} & =-12\end{aligned}\right. \)
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a) La solución del sistema es \(y = 0\) y \(x\) puede ser cualquier número real.
b) Las soluciones del sistema son \((x_1, y_1) = \left(3 + \frac{\sqrt{195}}{5}, \frac{3}{5(3 + \frac{\sqrt{195}}{5})}\right)\) y \((x_2, y_2) = \left(3 - \frac{\sqrt{195}}{5}, \frac{3}{5(3 - \frac{\sqrt{195}}{5})}\right)\).
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