What is the aqueous product of the reaction of \( \mathrm{Pb}(\mathrm{NO} 3) 2 \) and NaCl ? There is a solubility table in the course in Other Resources. NaNO 3 PbBr 2 PbNa \( \mathrm{Pb}(\mathrm{NO} 3) 2 \)

The reaction between lead(II) nitrate \(\mathrm{Pb(NO_3)_2}\) and sodium chloride \(\mathrm{NaCl}\) can be represented by the following double displacement (or metathesis) reaction: \[ \mathrm{Pb(NO_3)_2 (aq) + 2NaCl (aq) \rightarrow 2NaNO_3 (aq) + PbCl_2 (s)} \] In this reaction, lead(II) chloride \(\mathrm{PbCl_2}\) is formed as a precipitate because it is insoluble in water, while sodium nitrate \(\mathrm{NaNO_3}\) remains in the aqueous phase as it is soluble. Thus, the aqueous product of the reaction is \(\mathrm{NaNO_3}\), and the solid precipitate formed is \(\mathrm{PbCl_2}\).