A one-week study revealed that \( 60 \% \) of a warehouse store's customers are women and that \( 30 \% \) of women customers spend at least \( \$ 250 \) on a single visit to the store. Find the probability that a randomly chosen customer will be a woman who spends at least \( \$ 250 \).

To find the probability that a randomly chosen customer is a woman who spends at least \$250, we can use the information provided in the problem. 1. **Probability that a customer is a woman**: This is given as \( P(W) = 0.60 \) (or \( 60\% \)). 2. **Probability that a woman spends at least \$250**: This is given as \( P(S | W) = 0.30 \) (or \( 30\% \)), where \( S \) is the event that a customer spends at least \$250. To find the probability that a randomly chosen customer is a woman who spends at least \$250, we can use the multiplication rule of probability: \[ P(W \cap S) = P(W) \times P(S | W) \] Substituting the values we have: \[ P(W \cap S) = 0.60 \times 0.30 \] Calculating this gives: \[ P(W \cap S) = 0.18 \] Thus, the probability that a randomly chosen customer is a woman who spends at least \$250 is \( \boxed{0.18} \) or \( 18\% \).