Potter Evans
09/10/2024 · Elementary School
Resolver el sistema por el metodo de Eliminacion. Representa graficamente cada \( \begin{array}{l}2 x+5 y=1 \\ 6 x+7 y=3\end{array} \quad\left\{\begin{array}{l}3 x+3 y=10 \\ 3 x-5 y=20\end{array}\right. \)
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Para resolver los sistemas de ecuaciones por el método de eliminación, primero trabajaremos con cada sistema por separado. Primer sistema: \(2x + 5y = 1\) y \(6x + 7y = 3\). Solución: \((x, y) = \left(\frac{1}{2}, 0\right)\). Segundo sistema: \(3x + 3y = 10\) y \(3x - 5y = 20\). Solución: \((x, y) = \left(\frac{55}{12}, -\frac{5}{4}\right)\). Graficar las rectas de cada sistema para visualizar los puntos de intersección.
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