\( \left. \begin{array} { l } { \operatorname { es } 68 } \\ { ( \frac { 3 x + 1 } { x ^ { 2 } - a } + \frac { 2 } { 2 - x } ) : ( \frac { 3 } { a - x ^ { 2 } } ) = } \\ { ( \frac { 3 x + 1 } { x ^ { 2 } - a } + \frac { 2 } { 2 - x } ) : ( \frac { 3 } { a - x ^ { 2 } } ) = } \\ { ( \frac { 3 x + 1 } { ( x - 2 ) ( x + 2 ) } + \frac { z } { x - x } ) : ( \frac { 3 } { ( 2 - x ) ( } } \\ { ( \frac { 8 x + 1 } { ( x - 2 ) ( x + 2 ) } + \frac { 1 } { - x } ) \cdot ( \frac { 2 - x ) ( z x } { 1 } } \\ { - \frac { x + 1 } { ( x - 2 ) } + \frac { 1 } { - x } ) \cdot ( 2 - x ) = \frac { 2 } { 1 } } \\ { - x - 1 - \frac { 1 } { x } = 2 } \end{array} \right. \)

It seems like you've provided a series of mathematical expressions and equations, but they are somewhat jumbled and unclear. Let's break down the components and clarify what you might be looking for. 1. **Understanding the Expressions**: The expressions involve fractions, variables, and possibly some algebraic manipulation. It looks like there are several equations that might need to be solved or simplified. 2. **Identifying the Main Equation**: The last line appears to be a standalone equation: \[ -x - 1 - \frac{1}{x} = 2 \] 3. **Solving the Equation**: Let's solve the equation step by step. Starting with: \[ -x - 1 - \frac{1}{x} = 2 \] We can rearrange it: \[ -x - 1 = 2 + \frac{1}{x} \] \[ -x - 1 - 2 = \frac{1}{x} \] \[ -x - 3 = \frac{1}{x} \] Now, multiply both sides by \(x\) (assuming \(x \neq 0\)): \[ -x^2 - 3x = 1 \] Rearranging gives: \[ x^2 + 3x + 1 = 0 \] 4. **Using the Quadratic Formula**: We can solve this quadratic equation using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = 1\), \(b = 3\), and \(c = 1\): \[ x = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} \] \[ x = \frac{-3 \pm \sqrt{9 - 4}}{2} \] \[ x = \frac{-3 \pm \sqrt{5}}{2} \] 5. **Final Solutions**: The solutions for \(x\) are: \[ x = \frac{-3 + \sqrt{5}}{2} \quad \text{and} \quad x = \frac{-3 - \sqrt{5}}{2} \] If you have specific questions about the other expressions or need further assistance with them, please clarify, and I would be happy to help!