The equation of a line is $$ x+2=3 x-y $$. Where does this line cut the $$ X $$-axis? A -2 B 2 C -1 D 1

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The line cuts the $$ X $$-axis at $$ x = 1 $$. Therefore, the correct answer is D. 1. To find where the line cuts the $$ X $$-axis, we need to determine the point where $$ y = 0 $$. Starting with the given equation of the line: $$ x + 2 = 3x - y $$ We can rearrange this equation to isolate $$ y $$: $$ y = 3x - (x + 2) $$ Simplifying this gives: $$ y = 3x - x - 2 $$ $$ y = 2x - 2 $$ Now, to find the $$ X $$-intercept, we set $$ y = 0 $$: $$ 0 = 2x - 2 $$ Solving for $$ x $$: $$ 2x = 2 $$ $$ x = 1 $$ Thus, the line cuts the $$ X $$-axis at $$ x = 1 $$. The answer is $$ \boxed{1} $$.

The equation of a line is \( x+2=3 x-y \). Where does this line cut the \( X \)-axis? A -2 B 2 C -1 D 1

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The equation of a line is \( x+2=3 x-y \). Where does this line cut the \( X \)-axis? A -2 B 2 C -1 D 1

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