Martin Davison
09/24/2023 · High School
\( =r^{m} \) where \( r^{2}=x^{2}+y^{2}+z^{2} \), show that \( \frac{\partial^{2} V}{\partial x^{2}}+\frac{\partial^{2} V}{\partial y^{2}}+\frac{\partial^{2} V}{\partial z^{2}}=m(m+1) r^{m-2} \)
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Step-by-step Solution
To show that
\[
\frac{\partial^{2} V}{\partial x^{2}} + \frac{\partial^{2} V}{\partial y^{2}} + \frac{\partial^{2} V}{\partial z^{2}} = m(m+1) r^{m-2}
\]
where \( V = r^m \) and \( r^2 = x^2 + y^2 + z^2 \), we will use the chain rule and the properties of partial derivatives.
First, we express \( r \) in terms of \( x, y, z \):
\[
r = \sqrt{x^2 + y^2 + z^2}
\]
Now, we can compute the first derivatives of \( V \):
\[
\frac{\partial V}{\partial x} = \frac{\partial}{\partial x}(r^m) = m r^{m-1} \frac{\partial r}{\partial x}
\]
Next, we need to find \( \frac{\partial r}{\partial x} \):
\[
\frac{\partial r}{\partial x} = \frac{x}{r}
\]
Thus, we have:
\[
\frac{\partial V}{\partial x} = m r^{m-1} \cdot \frac{x}{r} = m r^{m-2} x
\]
Similarly, we can find the derivatives with respect to \( y \) and \( z \):
\[
\frac{\partial V}{\partial y} = m r^{m-2} y
\]
\[
\frac{\partial V}{\partial z} = m r^{m-2} z
\]
Now, we compute the second derivatives. Starting with \( \frac{\partial^2 V}{\partial x^2} \):
\[
\frac{\partial^2 V}{\partial x^2} = \frac{\partial}{\partial x} \left( m r^{m-2} x \right)
\]
Using the product rule:
\[
\frac{\partial^2 V}{\partial x^2} = m \left( \frac{\partial}{\partial x}(r^{m-2}) x + r^{m-2} \frac{\partial x}{\partial x} \right)
\]
Now we need \( \frac{\partial r^{m-2}}{\partial x} \):
\[
\frac{\partial r^{m-2}}{\partial x} = (m-2) r^{m-3} \frac{\partial r}{\partial x} = (m-2) r^{m-3} \cdot \frac{x}{r} = (m-2) r^{m-4} x
\]
Substituting this back into our expression for \( \frac{\partial^2 V}{\partial x^2} \):
\[
\frac{\partial^2 V}{\partial x^2} = m \left( (m-2) r^{m-4} x^2 + r^{m-2} \right)
\]
Now, we can write:
\[
\frac{\partial^2 V}{\partial x^2} = m (m-2) r^{m-4} x^2 + m r^{m-2}
\]
Next, we compute \( \frac{\partial^2 V}{\partial y^2} \) and \( \frac{\partial^2 V}{\partial z^2} \) in a similar manner:
\[
\frac{\partial^2 V}{\partial y^2} = m (m-2) r^{m-4} y^2 + m r^{m-2}
\]
\[
\frac{\partial^2 V}{\partial z^2} = m (m-2) r^{m-4} z^2 + m r^{m-2}
\]
Now, we sum these second derivatives:
\[
\frac{\partial^2 V}{\partial x^2} + \frac{\partial^2 V}{\partial y^2} + \frac{\partial^2 V}{\partial z^2} = m (m-2) r^{m-4} (x^2 + y^2 + z^2) + 3m r^{m-2}
\]
Since \( x^2 + y^2 + z^2 = r^2 \), we can substitute this into our equation:
\[
= m (m-2) r^{m-4} r^2 + 3m r^{m-2}
\]
\[
= m (m-2) r^{m-2}
Quick Answer
\[
\frac{\partial^2 V}{\partial x^2} + \frac{\partial^2 V}{\partial y^2} + \frac{\partial^2 V}{\partial z^2} = m(m-2) r^{m-2} + 3m r^{m-2}
\]
\[
= m(m+1) r^{m-2}
\]
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