Murphy Bowman
07/21/2024 · Elementary School

Fill in the blanks. Consider the equation \( \sqrt{7 x+1}=x-2 \). Squaring the left side and simplifying results in \( \ldots \) squaring the right side and simplifying resul Consider the equation \( \sqrt{7 x+1}=x-2 \). Squaring the left side and simplifying results in \( \sqrt{7} x+\sqrt{1} \). Squaring the right side and simplifying res

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uls in \( x^2-4x+4 \). Let's fill in the blanks with the correct expressions. Squaring the left side and simplifying results in \( \ldots \) squaring the right side and simplifying results in \( \ldots \). When we square the left side of the equation \( \sqrt{7 x+1}=x-2 \), we get: \[ (\sqrt{7 x+1})^2 = (x-2)^2 \] Simplifying the left side, we have: \[ 7 x + 1 \] Simplifying the right side, we have: \[ x^2 - 4x + 4 \] So, the blanks should be filled as follows: Squaring the left side and simplifying results in \( 7x + 1 \). Squaring the right side and simplifying results in \( x^2 - 4x + 4 \).

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Squaring the left side and simplifying results in \( 7x + 1 \). Squaring the right side and simplifying results in \( x^2 - 4x + 4 \).
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