Select the correct choice below and fill in the answer box within your choice it necessary. A. $$ 3 c^{2}-147=3\left(x^{2}-49\right) $$ B. The binomial is not factorable.

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A. $$ 3 c^{2}-147=3(c^{2}-49) $$ To determine whether the expression $$ 3c^{2}-147 $$ is factorable, we can start by factoring out the common factor. 1. Notice that both terms in $$ 3c^{2} - 147 $$ have a common factor of 3. We can factor that out: $$ 3c^{2} - 147 = 3(c^{2} - 49) $$ 2. Now, we can see that $$ c^{2} - 49 $$ is a difference of squares, which can be factored further: $$ c^{2} - 49 = (c - 7)(c + 7) $$ 3. Therefore, we can write the complete factorization of the original expression: $$ 3c^{2} - 147 = 3(c - 7)(c + 7) $$ Since we have successfully factored the expression, the correct choice is: **A. $$ 3 c^{2}-147=3\left(x^{2}-49\right) $$** However, it should be noted that the expression should be written as $$ 3(c^{2}-49) $$ instead of $$ 3(x^{2}-49) $$. So, the final answer is: **A. $$ 3 c^{2}-147=3(c^{2}-49) $$**

Select the correct choice below and fill in the answer box within your choice it necessary. A. \( 3 c^{2}-147=3\left(x^{2}-49\right) \) B. The binomial is not factorable.

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Select the correct choice below and fill in the answer box within your choice it necessary. A. \( 3 c^{2}-147=3\left(x^{2}-49\right) \) B. The binomial is not factorable.

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