Rose Henry
04/06/2023 · Elementary School
metro del triángulo cuyos vértices untos \( P_{1}(0,4) P_{2}(0,5) \) y \( P_{3}(12,4) \)
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Tutor-Verified Answer
Step-by-step Solution
Para encontrar el área del triángulo cuyos vértices son \( P_1(0,4) \), \( P_2(0,5) \) y \( P_3(12,4) \), podemos usar la fórmula del área de un triángulo dada por sus vértices \( (x_1, y_1) \), \( (x_2, y_2) \) y \( (x_3, y_3) \):
\[
\text{Área} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|
\]
Sustituyendo los puntos:
- \( P_1(0, 4) \) → \( (x_1, y_1) = (0, 4) \)
- \( P_2(0, 5) \) → \( (x_2, y_2) = (0, 5) \)
- \( P_3(12, 4) \) → \( (x_3, y_3) = (12, 4) \)
Sustituyendo en la fórmula:
\[
\text{Área} = \frac{1}{2} \left| 0(5 - 4) + 0(4 - 4) + 12(4 - 5) \right|
\]
Simplificando:
\[
\text{Área} = \frac{1}{2} \left| 0 + 0 + 12(-1) \right| = \frac{1}{2} \left| -12 \right| = \frac{1}{2} \cdot 12 = 6
\]
Por lo tanto, el área del triángulo es \( 6 \) unidades cuadradas.
Quick Answer
El área del triángulo es \( 6 \) unidades cuadradas.
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