Hart Kelly
12/28/2023 · Primary School
\( q = 199.86 \cdot ( 4.184 \frac { J } { g C } ) \cdot \Delta 9.3 \)
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Step-by-step Solution
It looks like you're trying to calculate the heat transfer \( q \) using the formula:
\[
q = m \cdot c \cdot \Delta T
\]
where:
- \( m \) is the mass (in grams),
- \( c \) is the specific heat capacity (in \( \frac{J}{g \cdot C} \)),
- \( \Delta T \) is the change in temperature (in degrees Celsius).
In your equation, you have:
- \( m = 199.86 \, g \)
- \( c = 4.184 \, \frac{J}{g \cdot C} \)
- \( \Delta T = 9.3 \, C \)
Now, substituting these values into the equation:
\[
q = 199.86 \cdot (4.184) \cdot (9.3)
\]
Now, let's calculate it step by step:
1. Calculate \( 4.184 \cdot 9.3 \):
\[
4.184 \cdot 9.3 = 38.8952
\]
2. Now multiply by the mass \( 199.86 \):
\[
q = 199.86 \cdot 38.8952 \approx 7775.56 \, J
\]
So, the heat transfer \( q \) is approximately \( 7775.56 \, J \).
Quick Answer
The heat transfer \( q \) is approximately \( 7775.56 \, J \).
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