Ball Medina
06/09/2023 · Primary School
Phthalonitrile \( \left(\mathrm{C}_{8} \mathrm{H}_{4} \mathrm{~N}_{2}\right) \) is produced by the ammoxidation of o-xylene \( \left(\mathrm{C}_{8} \mathrm{H}_{10}\right) \) according to the following reaction: \( \mathrm{C}_{8} \mathrm{H}_{10}(\mathrm{l})+\mathrm{O}_{2}(\mathrm{~g})+\mathrm{NH}_{3}(\mathrm{~g}) \rightarrow \mathrm{C}_{8} \mathrm{H}_{4} \mathrm{~N}_{2}(\mathrm{~s})+ \) \( \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \) How many grams of water would be produced by the complete ammoxidation of 22.50 moles of o-xylene? \[ \mathrm{g} \]
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The mass of water produced is approximately 405.34 grams.
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