Color blindness is a sex-linked genetic trait. If a mother is a bearer of the gene for colorblindnes but is not herself colorblind, and a father is also not color blind, each of their sons has a \( 50 \% \) probability of being colorblind. If these parents have 4 sons, the number who are colorblind has binomial distribution with \( n= \)

Solve \( x^{2}=20 \), where \( x \) is a real number. Simplify your answer as much as possible. If there is more than one solution, separate them with commas. If there is no solution, click "No solution."

d. \( \frac{1}{2} \mathrm{hm}=\quad \mathrm{m} \) \( \mathrm{s}=\mathrm{ssm}=\quad \mathrm{m} \)

Zado: ECOGRAFIA PELVICA GINECOLOGICA TR RNSYAGINAL

It can be shown that the algebraic multiplicity of an eigenvalue \( \lambda \) is always greater than or equal to the dimension of the eigenspace corresponding to \( \lambda \). Find \( h \) in the matrix A below such that the eigenspace for \( \lambda=6 \) is two-dimensional. \[ \left[\begin{array}{rrrr}6 & -3 & 9 & 6 \\ 0 & 3 & h & 0 \\ 0 & 0 & 6 & 5 \\ 0 & 0 & 0 & 1\end{array}\right] \] The value of \( h \) for which the eigenspace for \( \lambda=6 \) is two-dimensional is \( h=\square \).

\( \int \frac { x ^ { 4 } + 7 x ^ { 3 } + 45 x ^ { 2 } + 51 x + 23 } { 4 x ^ { 3 } + 13 x ^ { 2 } + 68 x - 60 } \)