(41) The thickness of DNA is about \( 3 \times 10^{-9} \) meter. The thickness of the smallest thing visible to the naked eye is \( 1 \times 10^{-4} \). (41) Compare the thickness of DNA to the smallest thing visible to the naked eye.

To compare the thickness of DNA to the smallest thing visible to the naked eye, we need to calculate the ratio of the thickness of DNA to the thickness of the smallest thing visible to the naked eye. Given: - Thickness of DNA = \( 3 \times 10^{-9} \) meters - Thickness of the smallest thing visible to the naked eye = \( 1 \times 10^{-4} \) meters Let's calculate the ratio of the thickness of DNA to the thickness of the smallest thing visible to the naked eye: \[ \text{Ratio} = \frac{\text{Thickness of DNA}}{\text{Thickness of the smallest thing visible to the naked eye}} \] Substitute the given values: \[ \text{Ratio} = \frac{3 \times 10^{-9}}{1 \times 10^{-4}} \] Now, let's simplify this expression to find the ratio. Calculate the value by following steps: - step0: Calculate: \(\frac{3\times 10^{-9}}{\left(1\times 10^{-4}\right)}\) - step1: Evaluate: \(\frac{3\times 10^{-9}}{10^{-4}}\) - step2: Separate the fraction: \(\frac{3}{1}\times \frac{10^{-9}}{10^{-4}}\) - step3: Divide: \(3\times \frac{10^{-9}}{10^{-4}}\) - step4: Divide: \(3\times 10^{-9-\left(-4\right)}\) - step5: Evaluate: \(3\times 10^{-5}\) The ratio of the thickness of DNA to the thickness of the smallest thing visible to the naked eye is \(3 \times 10^{-5}\). Therefore, the thickness of DNA is 3 orders of magnitude smaller than the thickness of the smallest thing visible to the naked eye.