Brewer Evans
01/22/2023 · Middle School

sof Equations and Inequalities with held questions: now vewng the questons you held earller. Please submit on onswer or pass. The marching band is selling candy bars and fruit snacks for a fundraiser. Candy bars are sold for \( \$ 2.50 \) and fruit snacks are \( \$ 1.50 \). A total of 650 items were sold, bringing in \( \$ 1,195 \). How many candy bars were sold?

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Let's denote the number of candy bars sold as \( x \) and the number of fruit snacks sold as \( y \). We are given the following information: 1. Candy bars are sold for $2.50 each. 2. Fruit snacks are sold for $1.50 each. 3. A total of 650 items were sold. 4. The total revenue from selling the items was $1,195. We can set up the following equations based on the given information: 1. The total number of items sold is 650: \( x + y = 650 \) 2. The total revenue from selling the items is $1,195: \( 2.50x + 1.50y = 1195 \) We can solve this system of equations to find the number of candy bars sold. Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}x+y=650\\2.5x+1.5y=1195\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x=650-y\\2.5x+1.5y=1195\end{array}\right.\) - step2: Substitute the value of \(x:\) \(2.5\left(650-y\right)+1.5y=1195\) - step3: Simplify: \(1625-y=1195\) - step4: Move the constant to the right side: \(-y=1195-1625\) - step5: Subtract the numbers: \(-y=-430\) - step6: Change the signs: \(y=430\) - step7: Substitute the value of \(y:\) \(x=650-430\) - step8: Simplify: \(x=220\) - step9: Calculate: \(\left\{ \begin{array}{l}x=220\\y=430\end{array}\right.\) - step10: Check the solution: \(\left\{ \begin{array}{l}x=220\\y=430\end{array}\right.\) - step11: Rewrite: \(\left(x,y\right) = \left(220,430\right)\) The solution to the system of equations is \( x = 220 \) and \( y = 430 \). Therefore, 220 candy bars were sold.

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220 candy bars were sold.
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