4) Count the dots: (1)) Then fill in the missing numbers: Submit tens \( +\square \) ones \( =20 \)

To solve the equation \( \text{tens} + \square \text{ ones} = 20 \), we need to express the tens in terms of the number of tens and the ones in terms of the number of ones. Let’s denote the number of tens as \( t \) and the number of ones as \( o \). The equation can be rewritten as: \[ 10t + o = 20 \] Now, we can find possible values for \( t \) and \( o \): 1. If \( t = 0 \): \[ 10(0) + o = 20 \implies o = 20 \] 2. If \( t = 1 \): \[ 10(1) + o = 20 \implies o = 10 \] 3. If \( t = 2 \): \[ 10(2) + o = 20 \implies o = 0 \] 4. If \( t \geq 3 \): \[ 10t \] would exceed 20, which is not possible. Thus, the possible combinations of tens and ones that satisfy the equation are: - \( t = 0 \), \( o = 20 \) - \( t = 1 \), \( o = 10 \) - \( t = 2 \), \( o = 0 \) Now, if we are looking for the missing number in the equation \( \text{tens} + \square \text{ ones} = 20 \), we can fill in the square with the corresponding number of ones based on the number of tens: - If \( t = 0 \), then \( \square = 20 \) - If \( t = 1 \), then \( \square = 10 \) - If \( t = 2 \), then \( \square = 0 \) Please specify which combination you would like to use, or if you need further assistance!