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Coffee Break prepares a blend of coffee containing Arabica beans and Brazil beans in the ratio \( 4: 3 \). (a) Calculate the weight of Arabica beans in a blend of 455 g .

b. Simplify fully \( 4 a^{2} b \times a^{4} b^{3} \)

b. \( f(x)=5 \cdot 3^{x} \) at \( x=-3 \)

Rotate the given triangle \( 180^{\circ} \) counter-clockwise about the origin. \( \left[\begin{array}{ccc}0 & -3 & 5 \\ 0 & 1 & 2\end{array}\right] \) \( \left[\begin{array}{lll}0 & {[?]} & {[ } \\ 0 & {[ } & {[ }\end{array}\right] \)