Gray Davey
03/27/2024 · Elementary School
Let \( f(x)=4+\frac{6}{x}+\frac{4}{x^{2}} \) \( f^{\prime}(x)=\square \) \( f^{\prime}(3)=\square \) \( f^{\prime \prime}(x)=\square \) \( f^{\prime \prime}(3)=\square \)
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Step-by-step Solution
Find the first order derivative with respect to \( x \) for \( 4+6/x+4/x^2 \).
Evaluate the derivative by following steps:
- step0: Evaluate the derivative:
\(\frac{d}{dx}\left(4+\frac{6}{x}+\frac{4}{x^{2}}\right)\)
- step1: Add the terms:
\(\frac{d}{dx}\left(\frac{4x^{2}+6x+4}{x^{2}}\right)\)
- step2: Use differentiation rules:
\(\frac{\frac{d}{dx}\left(4x^{2}+6x+4\right)\times x^{2}-\left(4x^{2}+6x+4\right)\times \frac{d}{dx}\left(x^{2}\right)}{\left(x^{2}\right)^{2}}\)
- step3: Calculate:
\(\frac{\left(8x+6\right)x^{2}-\left(4x^{2}+6x+4\right)\times 2x}{\left(x^{2}\right)^{2}}\)
- step4: Calculate:
\(\frac{x^{2}\left(8x+6\right)-2x\left(4x^{2}+6x+4\right)}{x^{4}}\)
- step5: Calculate:
\(\frac{-6x^{2}-8x}{x^{4}}\)
- step6: Rewrite the expression:
\(-\frac{6x^{2}+8x}{x^{4}}\)
- step7: Factor the expression:
\(-\frac{x\left(6x+8\right)}{x^{4}}\)
- step8: Reduce the fraction:
\(-\frac{6x+8}{x^{3}}\)
Substitute \( x=3 \) into the expression \( -\frac{6x+8}{x^{3}} \).
Evaluate the expression by following steps:
- step0: Evaluate:
\(-\frac{6x+8}{x^{3}}\)
- step1: Substitute:
\(-\frac{6\times 3+8}{3^{3}}\)
- step2: Multiply the numbers:
\(-\frac{18+8}{3^{3}}\)
- step3: Add the numbers:
\(-\frac{26}{3^{3}}\)
- step4: Simplify:
\(-\frac{26}{27}\)
Find the first order derivative with respect to \( x \) for \( -\frac{6x+8}{x^{3}} \).
Evaluate the derivative by following steps:
- step0: Evaluate the derivative:
\(\frac{d}{dx}\left(-\frac{6x+8}{x^{3}}\right)\)
- step1: Use differentiation rules:
\(-\frac{\frac{d}{dx}\left(6x+8\right)\times x^{3}-\left(6x+8\right)\times \frac{d}{dx}\left(x^{3}\right)}{\left(x^{3}\right)^{2}}\)
- step2: Calculate:
\(-\frac{6x^{3}-\left(6x+8\right)\times 3x^{2}}{\left(x^{3}\right)^{2}}\)
- step3: Calculate:
\(-\frac{6x^{3}-3x^{2}\left(6x+8\right)}{x^{6}}\)
- step4: Calculate:
\(-\frac{-12x^{3}-24x^{2}}{x^{6}}\)
- step5: Calculate:
\(\frac{12x+24}{x^{4}}\)
Substitute \( x=3 \) into the expression \( \frac{12x+24}{x^{4}} \).
Evaluate the expression by following steps:
- step0: Evaluate:
\(\frac{12x+24}{x^{4}}\)
- step1: Substitute:
\(\frac{12\times 3+24}{3^{4}}\)
- step2: Multiply the numbers:
\(\frac{36+24}{3^{4}}\)
- step3: Add the numbers:
\(\frac{60}{3^{4}}\)
- step4: Rewrite the expression:
\(\frac{3\times 20}{3^{4}}\)
- step5: Reduce the fraction:
\(\frac{20}{3^{3}}\)
- step6: Simplify:
\(\frac{20}{27}\)
The derivative of the function \( f(x)=4+\frac{6}{x}+\frac{4}{x^{2}} \) is \( f'(x)=-\frac{6x+8}{x^{3}} \).
Substitute \( x=3 \) into \( f'(x) \), we get \( f'(3)=-\frac{26}{27} \) or approximately -0.962.
The second derivative of the function is \( f''(x)=\frac{12x+24}{x^{4}} \).
Substitute \( x=3 \) into \( f''(x) \), we get \( f''(3)=\frac{20}{27} \) or approximately 0.740.
Quick Answer
\( f'(x)=-\frac{6x+8}{x^{3}} \), \( f'(3)=-\frac{26}{27} \), \( f''(x)=\frac{12x+24}{x^{4}} \), \( f''(3)=\frac{20}{27} \)
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