Vaughan Nguyen
10/05/2024 · Primary School
2. Dada id eadacion general \[ \begin{array}{ll}x^{2}+y^{2}+5 x+4 y+5=0 & h=\frac{-D}{2 A}\end{array} \]
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Para encontrar el centro de la circunferencia \( x^{2}+y^{2}+5x+4y+5=0 \), utilizamos la fórmula \( h = \frac{-D}{2A} \). Los coeficientes son \( A = 1 \), \( B = 5 \), \( D = 0 \), por lo que \( h = -\frac{5}{2} \). El centro es \( (-\frac{5}{2}, -2) \).
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