The actual yield is the mass of product actually created in the laboratory when the experiment is performed. Assume the following reaction was completed in the laboratory: \[ 3 \mathrm{C}(\mathrm{s})+\mathrm{Bi}_{2} \mathrm{O}_{3}(\mathrm{~s}) \rightarrow 2 \mathrm{Bi}(\mathrm{s})+3 \mathrm{CO}(\mathrm{g}) \] 19 g of carbon, C , reacted with 25 g of bismuth(III) oxide, \( \mathrm{Bi}_{2} \mathrm{O}_{3} \), resulting in the formation of 20 . g of bismuth, Bi . The following are the numerical values from the stoichiometry calculations: a. 19 g of carbon, C , formed 220 g of bismuth, Bi b. 25 g of bismuth(III) oxide, \( \mathrm{Bi}_{2} \mathrm{O}_{3} \), formed 22 g of bismuth, Bi What is the percent yield based on the given information?
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