5 (a) \( \begin{array}{l}\text { Tentukan sama ada kuantiti di bawah adalah kuantiti skalar atau kuantiti vektor. } \\ \text { Berikan justifikasi anda. } \\ \text { Determine whether the quantity below is a scalar quantity or a vector quantity. } \\ \text { Give your justification. } \\ \begin{array}{l}\text { Semasa pendaratan di atas tanah, ahli payung terjun membengkokkan kaki. Dengan cara } \\ \text { ini, dapat mengurangkan daya impuls dengan memanjangkan masa hentaman kaki } \\ \text { dengan tanah. } \\ \text { During landing on the ground, paratroopers bend their legs. In this way, it is possible to } \\ \text { reduce the impulse force by extending the impact time of the foot with the ground. }\end{array} \\ \text { [1 markah] } \\ \text { [1 mark] }\end{array} \)

How can prosecutors most directly influence law enforcement activity? Through their adherence to ethical standards Through their screening function Through their promotion of financial accountability Through their role as litigators

a) \( 51 / 2= \)

Evaluate the function at the specified points. \( h(x, y, z)=\frac{1}{x^{3}} y z,(2,6,-6),(3,-5,-3) \) At \( (2,6,-6) \) : \( \operatorname{At}(3,-5,-3) \) :

Ursula is a prosecutor who is deliberating on whether or not there is enough evidence to file charges against a man who was arrested two days ago for possession of an illegal substance with intentions to distribute. Which of the following will Ursula use when deciding whether to prosecute? Absolute immunity Precharge diversion Deferred prosecution diversion Prosecutorial discretion

[6.4] En los ejercicios 61-70 resuelve cada ecuación. \( \begin{array}{llll}\text { 61. } \frac{3}{4}=\frac{12}{x} & \text { 62. } \frac{x}{1.5}=\frac{x-4}{4.5} & \text { 63. } \frac{3 x+4}{5}=\frac{2 x-8}{3} & \text { 64. } \frac{x}{4.8}+\frac{x}{2}=1.7 \\ \text { 65. } \frac{2}{y}+\frac{1}{5}=\frac{3}{y} & \text { 66. } \frac{2}{x+4}-\frac{3}{x-4}=\frac{-11}{x^{2}-16} & \text { 67. } \frac{x}{x^{2}-9}+\frac{2}{x+3}=\frac{4}{x-3} \\ \text { 68. } \frac{7}{x^{2}-5}+\frac{3}{x+5}=\frac{4}{x-5} & \text { 69. } \frac{x-3}{x-2}+\frac{x+1}{x+3}=\frac{2 x^{2}+x+1}{x^{2}+x-6} & \text { 70. } \frac{x+1}{x+3}+\frac{x+2}{x-4}=\frac{2 x^{2}-18}{x^{2}-x-12}\end{array} \)